The City of Los Angeles envisions the day that every animal born is ensured a good home and good care. The Department of Animal Services is looking for one Veterinarian who desires to be part of our team by providing quality care to animals in the City’s animal care centers. We value the integrity of every employee, we care about our customers, and we are dedicated to the humane treatment of animals.
A Veterinarian diagnoses and gives first aid treatment, including surgery, to animals in the care and custody of the Department of Animal Services; assigns, reviews, and evaluates the work of employees assisting in the above work; advises the public and Department employees on matters within the field of veterinary medicine; and exercises medical judgment and skill in the independent performance of these responsibilities, applying current veterinary medical principles. This position will not be required to conduct spay and neuter surgeries.
• Doctor’s degree in veterinary medicine from an accredited veterinary school.
• Valid California State License to practice Veterinary medicine.
• Valid California driver’s license is required for all positions and must be maintained throughout employment.
Salary commensurate with experience up to $152,904 annually. Medical and dental benefits provided.
Cash retention bonuses available after six months ($1,000) and year two ($4,000) in accordance with the provisions of the current labor agreement.
How to apply
If you are interested in applying for this position, please submit a current resume, a City Employment Application, and proof of a doctor’s degree in veterinary medicine to email@example.com.
The period to submit your application opens on January 23, 2023 and ends when sufficient applications are received.
For candidates seeking initial City employment, in accordance with Los Angeles City Ordinance 187134, information regarding COVID-19 vaccination requirements as conditions of employment may be found at: https://clkrep.lacity.org/onlinedocs/2021/21-0921_ord_187134_8-24-21.pdf.